Question

 A two digit number is 4 times the sum of its digits.If 18 is added to the number ;

the digits are reversed .Find the number.

Answer 1

1.       Let the digits be x and y
Then the two-digit number is 10x + y
Given that: 10x + y = 4 (x + y) 
       10x + y = 4x + 4y
        6x = 3y
          y = 2x  --------------- 1
And 10x + y + 18 = 10y + x
Or           9y – 9x = 18 ---------------- 2
Substitute the value of y in eqn 2
18x – 9x = 18
9x = 18
x = 2
Therefore  y = 2x = 2*2 = 4
And the number is 10x + y = 10*2 + 4 = 24
Answer: The two-digit number is 24.
pls mark as brainliest
pls follow me
thanks

Answer 2

Let the number be 10x + y.
Now, 10x + y = 4( x + y)
10x + y = 4x + 4y
6x = 3y
2x = y....... (I)

Now, 10x + y + 18 = 10y + x
9x - 9y = -18
x - y = -2........(II)

From (I) and (II)
x = 2 and y = 4

Therefore, the number is 24.