a two digit number is 4 times the sum of the digits it is also equal to 3 times the product of the digits find the number
Answers
Answered by
8
Let the 2 digits be x and y
10x+y=4(x+y)--------------1)
y=4x+4y-10x
y =4y-6x
-3y=-6x
3y=6x
y=2x
10x+y=3xy------------------2)
4x+4y=3xy
4x+8x=6
12x=6
6x=12
x=2
y=2x
∴y=4
THE NUMBER IS 24
CHEERS!!
10x+y=4(x+y)--------------1)
y=4x+4y-10x
y =4y-6x
-3y=-6x
3y=6x
y=2x
10x+y=3xy------------------2)
4x+4y=3xy
4x+8x=6
12x=6
6x=12
x=2
y=2x
∴y=4
THE NUMBER IS 24
CHEERS!!
Answered by
6
Hi there...
here is the solution
let the two digits are X and Y
then the number is (10x+y)
now, according to question
(10x +y) =4(x +y)
=> 6x =3y
=> x = y/2 ........eq.(1)
also,
(10x+y) =3xy.......eq.(2)
put x=y/2 in eq.(2)
then,
10(y/2) + y = 3(y/2)y
=>5y +y = 3y²/2
=>3y²/2 -6y =0
multiplying by 2
=> 3y² -12y = 0
=>3y(y-4) =0
now either 3y =0 or, y-4=0
that is y = 0 , 4
then, x= y/2 = 0/2 =0
or, x = 4/2 = 2
here we consider nonzero values because the number is two digits
then, x=2 and y=4
Hence the number is (10×2 +4) =24
____________________________
Hope it helps......
here is the solution
let the two digits are X and Y
then the number is (10x+y)
now, according to question
(10x +y) =4(x +y)
=> 6x =3y
=> x = y/2 ........eq.(1)
also,
(10x+y) =3xy.......eq.(2)
put x=y/2 in eq.(2)
then,
10(y/2) + y = 3(y/2)y
=>5y +y = 3y²/2
=>3y²/2 -6y =0
multiplying by 2
=> 3y² -12y = 0
=>3y(y-4) =0
now either 3y =0 or, y-4=0
that is y = 0 , 4
then, x= y/2 = 0/2 =0
or, x = 4/2 = 2
here we consider nonzero values because the number is two digits
then, x=2 and y=4
Hence the number is (10×2 +4) =24
____________________________
Hope it helps......
Similar questions
10x+y=4(x+y)--------------1)
y=4x+4y-10x
y =4y-6x
-3y=-6x
3y=6x
y=2x
10x+y=3xy------------------2)
4x+4y=3xy
4x+8x=6[tex] x^{2} [/tex]
12x=6[tex] x^{2} [/tex]
6x=12
x=2
y=2x
∴y=4
CHEERS!!