a two digit number is 4 times the sum of the digits it is also equal to es the product of digit find the number
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Answered by
107
Here is your solutions
Let the one's digit be x.
ten's digit be y.
Original number = 10x + y
given that the number is four times the sum of the number, i.e., 4(x + y).
=> 10x + y = 4(x + y)
=> 10x + y = 4x + 4y
=> 10x - 4x + y - 4y = 0
=> 6x - 3y = 0
=> 3(2x - y ) = 0
=> 2x - y = 0
=> 2x = y
given that it is also equal to 3 times the product of digits, i.e, 10x + y = 3xy.
y = 2x and 10x+y = 3xy
on putting value of y = 2x in
=> 10x + y = 3xy.
=> 10x + 2x = 3x( 2x )
=> 12x = 6x²
=> 12x - 6x² = 0
=> 6x ( 2 - x) = 0
So, x = 0 and x = 2
x = 2
On putting value of x in y = 2x.
we get;
y = 2x
=> y = 2 × 2
=> y = 4
So,
Original number = 10x + y
=> 10 × 2 + 4
=> 20 + 4
=> 24
hope you happy
Let the one's digit be x.
ten's digit be y.
Original number = 10x + y
given that the number is four times the sum of the number, i.e., 4(x + y).
=> 10x + y = 4(x + y)
=> 10x + y = 4x + 4y
=> 10x - 4x + y - 4y = 0
=> 6x - 3y = 0
=> 3(2x - y ) = 0
=> 2x - y = 0
=> 2x = y
given that it is also equal to 3 times the product of digits, i.e, 10x + y = 3xy.
y = 2x and 10x+y = 3xy
on putting value of y = 2x in
=> 10x + y = 3xy.
=> 10x + 2x = 3x( 2x )
=> 12x = 6x²
=> 12x - 6x² = 0
=> 6x ( 2 - x) = 0
So, x = 0 and x = 2
x = 2
On putting value of x in y = 2x.
we get;
y = 2x
=> y = 2 × 2
=> y = 4
So,
Original number = 10x + y
=> 10 × 2 + 4
=> 20 + 4
=> 24
hope you happy
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Answered by
15
Solutions :-
Let the one's digit be x.
ten's digit be y.
Original number = 10x + y
given that the number is four times the sum of the number, i.e., 4(x + y).
=> 10x + y = 4(x + y)
=> 10x + y = 4x + 4y
=> 10x - 4x + y - 4y = 0
=> 6x - 3y = 0
=> 3(2x - y ) = 0
=> 2x - y = 0
=> 2x = y
given that it is also equal to 3 times the product of digits, i.e, 10x + y = 3xy.
y = 2x and 10x+y = 3xy
on putting value of y = 2x in
=> 10x + y = 3xy.
=> 10x + 2x = 3x( 2x )
=> 12x = 6x²
=> 12x - 6x² = 0
=> 6x ( 2 - x) = 0
So, x = 0 and x = 2
x = 2
On putting value of x in y = 2x.
we get;
y = 2x
=> y = 2 × 2
=> y = 4
So,
Original number = 10x + y
=> 10 × 2 + 4 => 20 + 4 => 24
Let the one's digit be x.
ten's digit be y.
Original number = 10x + y
given that the number is four times the sum of the number, i.e., 4(x + y).
=> 10x + y = 4(x + y)
=> 10x + y = 4x + 4y
=> 10x - 4x + y - 4y = 0
=> 6x - 3y = 0
=> 3(2x - y ) = 0
=> 2x - y = 0
=> 2x = y
given that it is also equal to 3 times the product of digits, i.e, 10x + y = 3xy.
y = 2x and 10x+y = 3xy
on putting value of y = 2x in
=> 10x + y = 3xy.
=> 10x + 2x = 3x( 2x )
=> 12x = 6x²
=> 12x - 6x² = 0
=> 6x ( 2 - x) = 0
So, x = 0 and x = 2
x = 2
On putting value of x in y = 2x.
we get;
y = 2x
=> y = 2 × 2
=> y = 4
So,
Original number = 10x + y
=> 10 × 2 + 4 => 20 + 4 => 24
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