Question

a two digit number is 6 more than 4 times the sum of its digit. if 27 is added to the number its digits are reversed. find the number​

Answer 1

Step-by-step explanation:

then answer is. 58 because let us take first condition as equation 1 and 2nd condition as equation 2 then by simplifying we get answe

Answer 2

Solution :

Let us assume that the number here is xy .

According to the first condition :

This number is 6 more than 4 times the sum of its digits .

> xy = 6 + 4(x+y)

> 10x + y = 6 + 4x + 4y

> 6x = 6 + 3y

> 2x = 2 + y .

> y = 2x - 2

This is an important result to be used in the following condition .

xy + 27 = yx

> 10x + y + 27 = 10y + x

> 9x + 27 = 9y

> x + 3 = y

But, y = 2x -2

Hence,

2x - 2= x + 3

> x = 5

> y = 8.

Thus , the required number becomes 58.

This is the answer,

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