Question

A two digit number is 6 times the sum of the digit.
If the digit at unit's place is increased by 3 and
the digit at ten's place is decreased by 3 and 18
is added to the numbers then the number of digits are
reversed, find the number ?

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Answer 1

Answer:

54

Step-by-step explanation:

Let the two digit number be (10x+y).

Here the digits are "x" and "y".

According to first condition,

10x+y=6(x+y)10x+y=6(x+y)

According to second condition,10(x-2)+(y+2)=4(x+y)10(x−2)+(y+2)=4(x+y)

So we get two simultaneous equations in two variables.

So the answer is 54

I hope you have understood it.