Question

A two-digit number is 7 more than three times the sum of the digits. If x is the digit at the tens place and y is the digit at the units place, write an equation in x and y

Answer 1

The number = 10(x) + y

The number = 10(x) + yThen ,

The number = 10(x) + yThen ,10(x) + y = 3(x+y)+7

10x+y=3x+3y+7

7x-7=2y

7(x-1)=2y

x=(2y/7)+1

Here you go...

Answer 2

Answer:

62 HOPE IT HELPS

Step-by-step explanation:

Let the digit at tens place be x and the digit unis place be y.

Then the original number will be 10x+y.

The digit at tens place is three times the digit at the units place.

i.e. x=3y ....(1)

The sum of this number and the number formed by reversing its digits is 88.

(10x+y)+(10y+x)=88

⇒11x+11y=88

⇒x+y=8 ....(2)

Substitute the value of equation (1) in equation (2).

Therefore, 3y+y=8

⇒4y=8

⇒y=2

Therefore, x=3y=3×2=6

Therefore, the original number is 62.