A two digit number is 7 times the sum of its digits. If the difference between the two digits is 2, find the number.
Please please answer it fast.
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let the two digit no. be 10x+y
a/q 10x+y = 7(x+y)
3x=6y
x=2y
and also x-y=2
2y-y=2
y=2
so x=1
but if y-x=2
then x=2
and y= 1
so the no.= 21
a/q 10x+y = 7(x+y)
3x=6y
x=2y
and also x-y=2
2y-y=2
y=2
so x=1
but if y-x=2
then x=2
and y= 1
so the no.= 21
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