Question

A two digit number is 7 times the sum of its digits. The number formed by

reversing its digits is less than the original number by 18. Find the original

number


pls send answer with all working​

Answer 1

Answer:

10a+b=7a+7b

10a+b−b=7a+7b−b

10a−7a=7a−7a+6b

3a3=6b3

a=2b

The number that is formed by reversing its digits is 18 less than the original number.

10b+a=10a+b−18

10b+2b=10(2b)+b−18

12b=21b−18

12b−21b=21b−21b−18

−9b−9=−189

b=2

If a=2b, then a=4

What is the number?

10(4)+2=7(4)+7(2)

40+2=28+14

42=42

10(2)+4=10(4)+2−18

20+4=40−16

24=24

So the original number is 42.

Answer 2

Answer:

Hope this will help you