A two digit number is 8 times sum of its digit. If we add 2 to 10's place digit and take 3 times of unit's digit then the number becomes 4/3 of the original number.Find the original number
pkhush256:
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Eq 1=10x+y=8(x+y),now eq 2=10(x+2)+3y=4*(10x+y) /3.now equate
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answer is 72.right or wrong
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I think you are right
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