Question

A two digit number is equal to 7 times the sum of its digits. The number formed by reversing
its digits is less than the original number by 18. Find the original number.

Answer 1

here is it answer...I'll be happy of I have succedd in helping u

Answer 2

Answer :

• The required number is 42.

Given :

• A two digit number is equal to 7 times the sum of its digits.

• The number formed by reversing
• its digits is less than the original number by 18.

To Find :

• The Number = ?

Step-by-step explanation :

Let x be the digit at ten ' s place and y be the digit at unit ' s place .

Then the number is 10x + y .

According to the first condition of the problem ,

10x + y = 7 ( x + y )

⟹ 10x + y = 7x + 7y

⟹ 3x = 6y

⟹ x = 2y ....(i)

The number formed by reversing the digits is 10y + x.

According to the second condition of the problem ,

10y + x = ( 10x + y ) - 18

⟹ 10y - y = 10x - x - 18

⟹ 9y = 9x - 18

⟹ y = x - 2

⟹ y = 2y - 2 [Using (i)]

⟹ y = 2.

From (i), x = 2 × 2 = 4

Hence the required number is 42.