Math, asked by korangavivek9, 1 month ago

A two-digit number is formed such that the sum of the digits is 13. When 45 is added to the number, the digits are reversed. Find the number... I will mark as brainliest.Tell correct answer​

Answers

Answered by satishdhanumuri55
1

Answer:

94

Step-by-step explanation:

x and y are the two digits

x+y=13

let x is in ten place then

10x+y+45=10y+x

10x-x+y-10y+45=0

9(x-y)=_45

x-y=_5

x+y=13

2x=8. x=4

y=13–4=9

Number =49

If 45 is added

49+45=94

Answered by chakundesupriya
1

Answer:

answer is 40

Step-by-step explanation:

x and y are two digit

x+y=13. let x is in ten place

10x +y +45=10y+x

10x-x+y-10y+45=0

9 x-y =-45

x-y=-5

2x=8. x=4

y=13-4 =9

number is=49

if 45 is added

49+45=94

the digit are reversed

Similar questions