Question

. A two digit number is formed with digits 0, 1, 2, 3, 4, 5 without repetition.

What is the probability that the number formed is

(i) an odd number (ii) a multiple of 5 (iii) a prime number

(iv) number formed is greater than 50.​

Answer 1

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Numbers are:

10,11,12,13,14,15,20,21,22,23,24,25,30,31,32,33,34,35,40,41,42,43,44,45

iii ) Prime number

11,13,23,29,31,41,43

P = $\frac{7}{20}$

ii ) A Multiple of 5

10,15,20,25,30,35,40

P = $\frac{4}{20}$

i ) An odd number

11,13,15,21,23,25,31,33,35,41,43,45

P = $\frac{12}{20}$

iv ) Number formed is greater than 50 .

P = $\frac{0}{50}$

Answer 2

Answer:

A two digit number is formed with digits 0, 1, 2, 3, 4, 5 without repetition.

What is the probability that the number formed is

(i) an odd number (ii) a multiple of 5 (iii) a prime number

(iv) number formed is greater than 50.​

Solution-

Step-by-step explanation:

Sample Space:

(10, 12, 13, 14, 15, 20 ,21, 23, 24, 25, 30, 31, 32, 34, 35, 40, 41, 42, 43, 45, 50, 51, 52, 53, 54)

n(S)=25

i) Odd number-

Event A= (13, 15, 21, 23, 25 , 31, 35, 41, 43, 45, 51, 53)

n(A)=12

p(A)=12/25

ii) Multiple of 5-

Event B= (10, 15, 20, 25, 30, 35, 40, 45, 50)

n(B)= 9

p(B)= 9/25

iii ) Prime number

Event C= (13,23,29,31,41,43

n(C)= 6

p(A)= 6/25

iv ) Number formed is greater than 50.

Event D= (51, 52, 53, 54)

n(D)= 4

p(D)= 4/25