Question

A two digit number is four times of its digit and twice the products of its digit. Find the number

Answer 1

Hey Dear here is Your Answer =)

*Let the digit in the ones place be x and tens place be y
Hence the two digit number = 10y + x
Given that the two digit number = 4 times sum of its digits
⇒ 10y + x = 4(x + y)
⇒ 10y + x = 4x + 4y
⇒ 3x – 6y = 0
⇒ 3x = 6y
∴ x = 2y → (1)
It is also given that the two digit number = 2 times product of its digits
⇒ 10y + x = 2xy
Divide by xy both the sides, we get..

=>10 / x + 1 / y = 2
=>5 / y + 1 / y = 2
=>6 / y = 2

∴ y = 3
Hence x = 6
The two digit number is (10y + x) = 10(3) + 6 = 36 


Hope it helps You Out =)
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Answer 2

Let the two digit number be 10x + y
Given two-digit number is four times the sum of its digits.
Therefore
10x + y = 4(x + y)
10x + y = 4x + 4y
6x - 3y = 0 
Taking 3 as common
2x - y = 0
2x = y

Also given that the number is twice the product of its digits
Therefore
10x + y = 2xy
Substituting the value of y = 2x
10x + 2x = 2x*2x
12x = 4x²
12/4 = x²/x
x = 3
y = 2(3) = 6

The number is 10(3) + 6 = 36.

Hope this helps you.