Question

a two digit number is four times the sum of its digit and twice the product . find the no.​

Answer 1

Answer:

Step-by-step explanation:

let the two digit number be 10x + y

according to the given question ,

Ist case

10x +y = 4(x+y)

10x +y = 4x +4y

10x - 4x = 4y - y

6x = 3y

divide by 3 throughout

2x = y

2x - y =0 ....[1]

2nd case

10x +y = 2(x+y)

10x +y = 2x+2y

10x -2x = 2y - y

8x = y

8x - y = 0....[2]

solve 1,2

2x - y = 0 [1]

8x - y = 0 [2]

subtract ;

we get - -6x = 0

x = 0

put x=0 in [1]

2(0) - y = 0

0-y = 0

y = 0

therefore the solution for this solution is x,y (0,0)