a two digit number is four times the sum of its digits and twice the product of its digits
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____________________________
Let the digit in the ones place be x and tens place be y
so the two digit number will be
=>
10y+x
And two digit number is four times the sum of the number
so
=> 4(X+y)
According to question
10y+X = 4(X+y)
=>
10y+X = 4x+4y
=>
x-4x = 4y- 10y
=>
-3x = -6y
X = 6y/3 = 2y
Now
it's two digit number is twice to the product
=>
10y+X = 2xy
put the value of X = 2y
=>
10y+2y = 2×2y×y
4y^2 = 12y
4y^2 = 12y
4y = 12
y =12/4
y = 3
put the value of y
X = 2×3
X= 6
hence the two digit number
36 Ans
Hope it's helpful ✌
____________________________
Let the digit in the ones place be x and tens place be y
so the two digit number will be
=>
10y+x
And two digit number is four times the sum of the number
so
=> 4(X+y)
According to question
10y+X = 4(X+y)
=>
10y+X = 4x+4y
=>
x-4x = 4y- 10y
=>
-3x = -6y
X = 6y/3 = 2y
Now
it's two digit number is twice to the product
=>
10y+X = 2xy
put the value of X = 2y
=>
10y+2y = 2×2y×y
4y^2 = 12y
4y^2 = 12y
4y = 12
y =12/4
y = 3
put the value of y
X = 2×3
X= 6
hence the two digit number
36 Ans
Hope it's helpful ✌
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