A two - digit number is four times the sum of its digits. if 27 were added to the number, it becomes seven times the sum of digits.find the number.
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let 1st digit =x
2nd digit = y
therefore no. =10x+y
10x+y(when added) is 4 times less than the no.
there fore (x+y)*4=10x+y find eq 1
eq 2 =(x+y) *7=(10x+y)+27
2nd digit = y
therefore no. =10x+y
10x+y(when added) is 4 times less than the no.
there fore (x+y)*4=10x+y find eq 1
eq 2 =(x+y) *7=(10x+y)+27
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