Question

A two digit number is greater by 4 than 8 times the sum of the digits. If 7 times the tens place digit is subtracted from the given number, the new number obtained is that obtained by interchanging the digits of the original number. Find the given two digit number.​​

Answer 1

Step-by-step explanation:

let, consider two digit are x and y.

the number is =(10*x+y)

according to the problem,

8(x+y)+4=(10*x+y).................(1)

according to the problem,

( 10*x+y)-7x=(10*y+x)................(2)

then from equation (1),

(8x + 8y)+4=10x +y

2x -7y=4............(3)

then from equation (2),

(10*x +y)-7x=10y+ x

2x -9y=0.......(4)

then from equation (3) and (4),

(2x-7y)-(2x-9y)=4-0

2y = 4

y= 2

if y=2 then putting in equation (3)

2x-7y=4

2x-(7*2)=4

2x = 4+14=18

x=(18/2)=9

then, x=9 and y=2

the number is =(9*10+2)=92

Answer 2

Step-by-step explanation:

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