Question

A two digit number is increased by 18.when the digits are reversed the sum of digits is 6.find the reversed digit.

Answer 1

Please see the attachment

Answer 2

x+y=6 (eq 1)
so...
10x+y (since a 2 digit number)
10y+x (hence...reversed)
so...
10y+x=10x+y+18
9y-9x=18
9(y-x)=18
y-x=2
x=y-2

putting value in eq 1

x+y=6
y-2+y=6
y=4
hence
x=2
so 24 and 42 are answers