Question

A two digit number is made of two consecutive digits such that the sum of the square is 4 less than the number find the two digit number

Answer 1

Answer:

Let one place digit be x and ten place digit be (x + 1) of two digit number.

Then,

Number = 10*(x + 1) + x

= 11x + 10

As per given condition

x^2 + (x + 1)^2 = (11x + 10) - 4

x^2 + x^2 + 1 + 2x = 11x + 6

2x^2 - 9x - 5 = 0

2x^2 - 10x + x - 5 = 0

2x(x - 5) + 1(x - 5) = 0

(2x + 1)(x - 5) = 0

x = - 1/2, 5

Negative value not possible

Therefore,

Two digit number

= 11*5 + 10