a two digit number is obtained by either multiplying sum of the digits by 8 and adding 1 or by multiplying the difference of the digits by 13 and adding 2 . Find the numbers.
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hi payal ,
Let the two digit number be 10x+y
A two digit number is obtained by
multiplying sum of the digits by 8 and adding 1
10x+y = (x+y)8 + 1
10x+y = 8x + 8y + 1
2x = 7y + 1
x= 3.5y +0.5
or by multiplying the difference of the digits by 13 and adding 2
10x+y = (x-y)13 + 2
10x+y = 13x - 13y + 2
3x = 14y - 2
substituting x value in above equation
3(3.5y + 0.5) = 14y -2
10.5y + 1.5 = 14y -2
3.5y = 3.5
y = 1
so
x = 3.5y + 0.5 = 3.5 + 0.5 = 4
hence the required two digit number is 10x+y = 40+1 = 41
Hope it helped.
Let me know if any doubts.
Cheers !!!
Let the two digit number be 10x+y
A two digit number is obtained by
multiplying sum of the digits by 8 and adding 1
10x+y = (x+y)8 + 1
10x+y = 8x + 8y + 1
2x = 7y + 1
x= 3.5y +0.5
or by multiplying the difference of the digits by 13 and adding 2
10x+y = (x-y)13 + 2
10x+y = 13x - 13y + 2
3x = 14y - 2
substituting x value in above equation
3(3.5y + 0.5) = 14y -2
10.5y + 1.5 = 14y -2
3.5y = 3.5
y = 1
so
x = 3.5y + 0.5 = 3.5 + 0.5 = 4
hence the required two digit number is 10x+y = 40+1 = 41
Hope it helped.
Let me know if any doubts.
Cheers !!!
jish4you:
hope u liked my solution
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