a two digit number is obtained by either multiplying sum of digits by 8 and adding 1 or by multiplying the difference of digits by 13 and adding 2 find the number
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2
Let ten's digit = z and unit digit = y.
10x + y = 8(x+y) + 1
&
10x + y = 13(x-y)+2
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number 41
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Answer: hope it is helpful
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