A two digit number is obtained by either multiplying the sum of digits by 8 and then subtracting 5 or by multiplying the difference of digits by 16 and adding 3. Find the number.
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Heyaa♡♡
Here is the answer :-
Let the unit digit and the ten's digit of the number be x and y respectively.
Therefore the number = 10y + x.
Sum of digits of digits = x+y
10y + x = 8(x+y) - 5
10y + x = 8x + 8y = - 5
7x - 2y = 5 -------- i)
Difference of the digits = y-x [if x<y ]
10y + x = 16 (y-x) + 3
10y + x = 16y - 16x + 3
17x - 6y = 3 -------- ii)
Multiply eq(1) by 3 and subtracting eq(2):
21x - 6y = 15
17x - 6y = 34
x = 12x
= 12 / 4 = 3
Substitute x = 3 in eqn (1).
7* 3 - 2y = 5
2y = 21 - 5
2y = 16y
= 16 / 2 = 8
Thus the unit digit of the number is 3 and ten's digit is 8 .
Thus number is 83
Hope it helped you.
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