Question

A two digit number is obtained by either multiplying the sum of the digits by 8 and adding 1 or by multiplying numbers how many such numbers are there? ​

Answer 1

$\huge\underbrace\purple{\dag QueStiÖn\dag}$

A two digit number is obtained by either multiplying the sum of the digits by 8 and adding 1 or by multiplying numbers how many such numbers are there?

$\huge\underbrace\purple{\dag AnsWeŘ\dag}$

$\huge\underbrace\purple{\dag In \; AttaĆhmËnț\dag}$

Answer 2

Step-by-step explanation:

Answer

Let the digit at units place be x and the digit at ten's place be y. Then,

Number =10y+

According to the given conditions, we have

10y+x=8(x+y)+1⇒7x−2y+1=0

and, 10y+x=13(y−x)+2⇒14x−3y−2=0

By using cross-multiplication, we have

−2×−2−(−3)×1

x

=

7×−2−14×1

−y

=

7×−3−14×−2

1

⇒

4+3

x

=

−14−14

−y

=

−21+28

1

⇒

7

x

=

28

y

=

7

1

⇒x=

7

7

=1 and y=

7

28

=4

Hence, the number =10y+x=10×4+1=41.