A two digit number is obtained by eithermultiplying thesum of digits by 8 and 1 or by multiplying number How many such number s are thes
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xy be the numbers , x is two digit number and y is one digit,
8(x +y)+ 1 = 10x + y ;
13(x -y) + 2 = 10 x + y
we get, 8x + 8y + 1 = 10x + y, we get the value as 2x - 7y =1
13x - 13y + 2 = 10x + y, we get the value as 3x - 14y = -2
through elimination we get, x = 4 , y = 1, the number is 41
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