A two digit number is obtained by multiplying the sum of the digit by 8 also it is obtained by multiplying the difference of the digit by 14 and adding 2 find the number
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Let the number be 10*x +y
ATQ
From 1st condition
>>(x+y)*8 = 10*x + y
>> 2x = 7y ...(1)
From 2nd condition
>> (x -y) *14 + 2 = 10*x + y
>> 4x -15y + 2 = 0 ...(2)
From (1) and (2)
put value of x in eq (2)
14y -15y + 2 = 0
>> y = 2
>> 2x = 7*2 (putting value of y in eq (1))
x = 7
y = 2
Therefore the number = 10*x + y = 72
ATQ
From 1st condition
>>(x+y)*8 = 10*x + y
>> 2x = 7y ...(1)
From 2nd condition
>> (x -y) *14 + 2 = 10*x + y
>> 4x -15y + 2 = 0 ...(2)
From (1) and (2)
put value of x in eq (2)
14y -15y + 2 = 0
>> y = 2
>> 2x = 7*2 (putting value of y in eq (1))
x = 7
y = 2
Therefore the number = 10*x + y = 72
neosingh:
2nd eq is multiplying the difference of the digit by 14 and adding 2
How
from (1) 4x =14y put this in eq (2)
get it?
How do you get the values of x and y
i have edited the ans
check if u understand now
Where is the value of x in eq 1
x= 7y/2
Thanks I understood it correctly
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