a two digit number is seven times the sum of its digit .if the difference between two digits is two.find the number
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let two digit number be 10A+B,
then
10A+B=7(A+B),
10A+B=7A+7B,
10A-7A+B-7B=0,
then
3A-6B=0,
then
A-2B=0,...........eq(1),
also
A-B=2,..................eq(2),
on solving these two equations, we have
A=4,
B=2,
therefore
two digit number =10×4+2=42✓✓✓✓
then
10A+B=7(A+B),
10A+B=7A+7B,
10A-7A+B-7B=0,
then
3A-6B=0,
then
A-2B=0,...........eq(1),
also
A-B=2,..................eq(2),
on solving these two equations, we have
A=4,
B=2,
therefore
two digit number =10×4+2=42✓✓✓✓
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