a two digit number is seven times the sum of its digits.the number formed by reversing the digit is 6 more than half of the original number .find the numbers
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hey mate here is your answer ❤️❤️❤️❤️❤️
let the digit of units place be x and the digit of tens place be y
then the number is(10y+x)
(10y+x)=7(y+x)
10y+x=7y+7x
3y-6x=0.
y=6x/3. --------(I)
(10x+y)=1/2(10y+x)+10
10x+y=10y/2+x/2+10
10x+y=(10y+x+20)/2
20x+2y=10y+x+20
19x-8y-20=0
substituting y
we get
19x-8(6x/3)-20=0
57x-48x-60=0
9x=60
x=6.6
y=6×6.6/3
y=13.2
therefore the number is 138.6
let the digit of units place be x and the digit of tens place be y
then the number is(10y+x)
(10y+x)=7(y+x)
10y+x=7y+7x
3y-6x=0.
y=6x/3. --------(I)
(10x+y)=1/2(10y+x)+10
10x+y=10y/2+x/2+10
10x+y=(10y+x+20)/2
20x+2y=10y+x+20
19x-8y-20=0
substituting y
we get
19x-8(6x/3)-20=0
57x-48x-60=0
9x=60
x=6.6
y=6×6.6/3
y=13.2
therefore the number is 138.6
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