A two digit number is six times the sum of its digits. The sum of original number and the number obtained by interchanging the digits is 99. Find the number.
Answers
Answer:
Answer:Let the digit in the unit's place be x and the digit in the ten's place be y . Then,
Answer:Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+x
Answer:Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+y
Answer:Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,
Answer:Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99
Answer:Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99=11x+11y=99
Answer:Let the digit in the unit's place be x and the digit in the ten's place be y . Then,Number=10y+xThe number obtained by interchanging the digits is 10x+yAccording to the given conditions,(10y+x)+(10x+y)=99=11x+11y=99=x+y=9 -----1
1And,x−y=±3 -----2 (given)
2 (given)On solving equation 1 and 2 ,we get
2 (given)On solving equation 1 and 2 ,we getx=6,y=3 or x=3,y=6