Question

A two digit number is such that its tens digit is 6 more than the unit's digit. also the teens digit is three times the units digit. Find the number.

Answer 1

Answer :

$\large{ \star\:\:\boxed{\bf{The\:Required\:Number\:is\:93\:.}}\:\:\star }$

Explanation :

Given :–

• The tens digit is 6 more than the ones(unit) digit .
• Tens digit is 3 times ones(unit) digit .

To Find :–

• The required number .

Solution :–

Let the Tens digit of the Number be x and the Ones digit be y .

☆ According to the First Condition :-

$\implies\sf{x\:=\:y\:+\:6}\:\:-----\bf{(1)}$

☆ According to the Second Condition :-

$\implies\sf{x\:=\:3y}\:\:-----\bf{(2)}$

Now , putting the value of 'x' from Equation(2) in Equation(1) :-

$\rightarrow\sf{3y\:=\:y\:+\:6}$

$\rightarrow\sf{3y\:-\:y\:=\:6}$

$\rightarrow\sf{2y\:=\:6}$

$\rightarrow\sf{y\:=\:\dfrac{6}{2} }$

$\rightarrow\boxed{\bf{y\:=\:3 }}$

Putting this value of 'y' in Equation(1) :-

$\rightarrow\sf{x\:=\:3\:+\:6}$

$\rightarrow\boxed{\bf{x\:=\:9}}$

★ As we know that a two - digit number is in the form of :

→ 10(x) + (y)

→ 10(9) + (3)

→ 90 + 3

→ 93

∴ The Required Number is 93 .

Answer 2

❥$\:\:\Large{\underline{\underline{\bf{\red{Given}}}}}\: :$

• The tens digit is 6 more than the ones(unit) digit
• Tens digit is 3 times ones(unit) digit

❥$\:\:\Large{\underline{\underline{\bf{\blue{To\:Find}}}}}\: :$

• The required number

❥$\:\:\Large{\underline{\underline{\bf{\pink{Solution}}}}}\: :$

Let,

• The Tens digit of the Number be x
• The Ones digit be y

$\leadsto\bf\red{x\:=\:y\:+\:6}\:\:.........(1)$

$\leadsto\bf\red{x\:=\:3y}\:\:.........(2)$

Putting 'x' value from Eq (2) in Eq (1) :-

$\to\:\:\sf\purple{3y\:=\:y\:+\:6}$

$\to\:\:\sf\green{3y\:-\:y\:=\:6}$

$\to\:\:\sf\purple{2y\:=\:6}$

$\to\:\:\sf\green{y\:=\:\dfrac{\cancel{6}^{\:\:3}}{\cancel{2}_{\:1}} }$

$\to\:\:\sf\underline\red{y\:=\:3 }$

Putting value of 'y' in Eq (1) :-

$\mapsto\:\:\sf\purple{x\:=\:3\:+\:6}$

$\mapsto\:\:\sf\underline\red{x\:=\:9}$

Now, finding the required number. As we know that two digit number is in the form of :

$\leadsto\:\:\sf\blue{ 10(x)\:+\:(y)}$

$\leadsto\:\:\sf\orange{ 10(9)\:+\:(3)}$

$\leadsto\:\:\sf\blue{ 90\:+\:3}$

$\leadsto\:\:\sf\orange{ 93}$

✫ ${\underline{\underline{\bf{\red{The\: Required\: Number\: is \:93 }}}}}$