Question

A two digit number is such that sum of its digit is 13. If 9 is subtracted from the number it digits

reversed. Find the number​

Answer 1

Answer:

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Step-by-step explanation:

Let the 2 digit number be 10a + b, where a and b are the tens digit and the ones digit.

Given that

a + b = 13 (equation 1) and

10a + b —9 = 10b + a (equation 2)

So 9a = 9b + 9 , which means

a = b + 1 (equation 3)

Substitute (3) into (1)

(b + 1) + b = 13

2b = 12

b = 6 (equation 4)

Substitute (4) into (3)

a = 6 + 1 = 7 (equation 5)

The 2 digit number is 76.

Answer 2

Step-by-step explanation:

According to the question :-

let x and y be the number so :-

x + y = 13 ---------( 1 )

10x + y - ( 10y + x ) = 9

9y - 9x = 9

x - y = 1 ---------( 2 )

Adding ( 1 ) from ( 2 ) equation

2x = 14

x = 7 and y = 6

So 76 is the right answer of this question

if we subtract 9 from them then it become 67 which is reverse of this number.

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