A two digit number is such that sum of its digits is 3 time the difference of digits. If the number is
neither prime nor a perfect square. Then how many such two digit are possible?
give correct answer if you know if you give wrong answer I will report you
Answers
Given : two digit number is such that sum of its digits is 3 time the difference of digits . number is neither prime nor a perfect square.
To find : how many such two digit numbers are possible
Solution:
Let say number is AB or BA where A > B
A + B = 3( A - B )
=> A + B = 3A - 3B
=> 2A = 4B
=> A = 2B
B can be 1 , 2 , 3 , 4
A can be 2 , 4 , 6 , 8
Possible numbers are
12 , 24 , 36 , 48 , 21 , 42 , 63 , 84
12 , 21 , 24 , 36 , 42 , 48 , 63 , 84
none of the Numbers is prime
36 is only perfect Square so
Number left are
12 , 21 , 24 , 42 , 48 , 63 , 84
7 such two digit Numbers are possible
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