Math, asked by mayankanand73, 1 year ago

A two digit number is such that the product of its digit is 18. When 63 is subtracted from the number the digits interchange thier places. Find the number. ​

Answers

Answered by aditykhebade2012
3

Answer:

Step-by-step explanation:

let the Units place be x and Tens be y

By the given statements

xy=18...........(1)

10x + y - 63 = 10 y + x

9x - 9y - 63= 0

9x - 9y = 63

x-y = 7..........(.2)

x= 7+y

put value of x in eq 1, we get

( 7+y ). y = 18

y² + 7y = 18

y² +7y-18=0

y² +9y -2y -18= 0

y(y+9) -2 ( y +9) =0

( y+9) (y-2). = 0

y=-9 , y = 2

y= 2........

so, x= 7+2=9

therefore the two digit number is 10(9)+2

= 92


mayankanand73: bhai me aapko agar aur questions du
mayankanand73: u can do it
aditykhebade2012: maybe?
Answered by mamathaamin0
0

Answer:

Step-by-step explanation:

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