A two-digit number is such that the product of its digits is 14 .if 45is added to the number the digits interchange their places.find the number
Answers
Answer:
the answer is 27.
Step-by-step explanation:
let the two no. are X and y.
then x × y = 14 equation 1...
y = 14/x
now according to the questions
( 10 X + y) + 45 = ( 10 y + x )
( 10 X + 14/x ) + 45 = ( 10 × 14/x + x)
( 10x² + 14 + 45x ) = ( 140 + x² )
9x² + 45x -126=0
x= 2, -7
we only take positive value
so x= 2
y = 14/2
= 7
so the no. are 27
and 27 + 45 = 72.
Answer:
27
or
-72
Step-by-step explanation:
Let the digits of the two digit number be x and y .
So the number = 10x + y
According to Question ,
The product of the digits is 14
Therefore ,
Again , it is given that if 45 is added to the number , the digits interchange there position .
Thus
Therefore , the value of y will be :
Now using the value of y in (1) we have :
When x = 2 and y = 7
The number is
10×2 + 7
= 20 + 7
= 27
Again , when x = -7 and y = -2
The number is
10×(-7) -2
=-70-2
= -72
Verification :
The product of digits
★ First case :
7×2
= 14
★ second case
(-7)×(-2)
= 14
When 45 is added then digits interchange their position
★ First case : adding 45
27 + 45
= 72 (interchanged)
★ Second case : adding 45
-72 + 45
=-27 ( interchanged)