A two digit number is such that the product of its digits is 18.When 63 is subtracted from the number, the digits interchange their places. Find the number
Answers
Answer:
Answer is 92.
Let the number be 10x+y
According to question,
10x+y−63=10y+x
⇒10x−x+y−10y=63
⇒9x−9y=63
⇒x−y=7
⇒x=7+y (i)
xy=18 (ii)
Substituting the value of x in (ii) we get,
(7+y)y=18
⇒y2+7y−18=0
⇒y2+9y−2y−18=0
⇒y(y+9)−2(y+9)=0
⇒(y+9)(y−2)=0
⇒y=−9 and y=2
y=−9 is not valid
∴y=2
Putting the value of y in (i) we get,
x−2=7
⇒x=7+2
⇒x=9
So the number =10x+y=10(9)+2=92
Hope this helps you
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- The product of the digits of a two digit number is 18.
- When 63 is subtracted from the original number, the digits interchange their places.
- What is the original number ?
Let the digit at ten's place be 'x' and the digit at the unit's place be 'y'
CASE:- 1)
✧ The product of the digits of a two digit number is 18
➠ xy = 18...❶
CASE:- 2)
✧ When 63 is subtracted from the original number, the digits interchange their places
❮ Reversed Number = 10y + x ❯
➠ 10x + y –63 = 10y + x
➠ 10x + y –10y –x = 63
➠ 9x –9y = 63
Take common '9' from both sides
➠ x –y = 7
➠ x = 7 + y...❷
Put the value of 'x' from equation 2) in equation 1)
➠ (7 + y)y = 18
➠ 7y + y² = 18
➠ y² +7y –18 = 0
➠ y² +(9 –2)y –18 = 0
➠ y² +9y –2y –18 = 0
➠ y(y +9) –2(y +9) = 0
➠ (y –2) (y +9) = 0
Put the value of 'y' in equation 2), we get
➠ x = 7 + 2
❒ NUMBER = 10x + y
❒ NUMBER = 10(9) + 2
❝ Hence, the number formed is 92 ❞