A two-digit number is such that the product of its digits is 6. When 9 is added to this number; the digits interchange their places. Find the number.
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let 2 digit no be XY
X× Y= 6
XY + 9 = YX
10 X + Y + 9= 10 Y + X
9X - 9 Y+ 9=0
X- Y + 1=0
ALSO X× Y = 6
X= 6/Y
put in x- y+1=0
6/y - y +1=0
6 - y.y+ y= 0
-y.y -2y + 3y +6 =0
-y(y+2) +3(y+2) =0
y= 3,-2
take y=3
x= 6/3 = 2
SO number is 23
X× Y= 6
XY + 9 = YX
10 X + Y + 9= 10 Y + X
9X - 9 Y+ 9=0
X- Y + 1=0
ALSO X× Y = 6
X= 6/Y
put in x- y+1=0
6/y - y +1=0
6 - y.y+ y= 0
-y.y -2y + 3y +6 =0
-y(y+2) +3(y+2) =0
y= 3,-2
take y=3
x= 6/3 = 2
SO number is 23
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I hope it helps you mate
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