a two digit number is such that the product of the digit is 14. when 45 is added to the number, then the digit interchange their place. find the number
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xy=14
x=14/y
10x +y +45 = 10y+x
x-y=-5
14/y - y=-5
14 -y^2=-5y
y^2 -5y -14
y =7
x=2
=27
x=14/y
10x +y +45 = 10y+x
x-y=-5
14/y - y=-5
14 -y^2=-5y
y^2 -5y -14
y =7
x=2
=27
hanif2673:
thanx dear
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