A two-digit number is such that the product of the digit is 12. When 36 is added to the no. The digits interchange their places. Find the two digit number???????
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Let the 2 digit number be 'ab'
Given 10a + b + 36 = 10b + a
10b + a - (10a + b) = 36
9b - 9a = 36
9(b-a) = 36
b-a = 4
Hence the possibilities are (5,9) , (4,8), (3,7), (2,6) , (1, 5)
Given the product of digits = 12
a*b = 12
From the above possibilities only '26' satisfies.
Hence '26' is the 2-digit number.
Given 10a + b + 36 = 10b + a
10b + a - (10a + b) = 36
9b - 9a = 36
9(b-a) = 36
b-a = 4
Hence the possibilities are (5,9) , (4,8), (3,7), (2,6) , (1, 5)
Given the product of digits = 12
a*b = 12
From the above possibilities only '26' satisfies.
Hence '26' is the 2-digit number.
Let the first digit be x and the second digit be y
yep
The product. Xy=12
x=12÷y
from second statement. 10x+y+36=10y+a
Substitute 12÷y for x
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I really apologize for the presentation.... actually I decided to try it, but then discovered its correct coz the other answer and my answer matches.
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