A two digit number is such that the product of the digits is 12. When 36 is added
te the number the digits interchange their places. Formulate the quadratic equation whose
roots) is lare) digit(a) of the number
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let number = 10x + y
according to question,
xy = 12 --------(1)
again,
10x + y + 36 = 10y + x
9x - 9y = 36
x - y = 4
x = 4 + y
put this in equation (1)
y( y + 4) = 12
y² + 4y -12= 0
hence, quadratic equation ,
is y² + 4y -12 = 0
solve this y = 6, but y ≠ -2
then , x = 2
so,number= 10×2 + 6 =26
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