Question

A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is​

Answer 1

Answer:

26

Step-by-step explanation:

let unit digit=x

tens digit=y

xy=8

number=10y+x

now 10y+x+18=10x+y

        9x-9y=18

x-y=2

(x-y)^2=(x+y)^2-4xy

4+32=(x+y)^2

x+y=6       x=4  y=2

Answer 2

Answer:

24

Step-by-step explanation:

Let the ten's and unit digit be x and 8/x respectively.

Then (10x + 8/x) + 18 = 10x * 8/x + x

10x2 + 8 + 18x = 80 + x2

9x2 + 18x - 72 = 0

x2 + 2x - 8 = 0

(x + 4)(x - 2) = 0

x = 2

8/2 = 4

24