Math, asked by nithish5627, 1 year ago

A two digit number is such that the product of the digits is 12. when 36 is added to the number the digits interchanging their places. find the two digit number.

Answers

Answered by kaira1818
13

let the digit in ones place be x

and the digit in tens place be y

therefore, the two digit no. = 10y+x

the reversing no. = 10x+y

A/Q,

xy=12

=>x=12/y

and,

10y+x+36=10x+y

=>10y-y+x-10x = - 36

=>9y - 9x = - 36

=> y - x = - 36/9

=>y -12/y = - 4

=>(ysq. - 12)/y = - 4

=> ysq. - 12 = -4y

=> y sq. +4y -12 = 0

=> y sq. +4y-3y - 12 = 0

=> y(y+4) - 3 (y+4) = 0

=> (y+4)(y-3) = 0

either y= -4(not possible) or y= 3

therefore, y=3,x=12/3= 4

the req. 2 digit no. = 10*3 + 4 = 34


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