A two digit number is such that the sum of digits is 6. If 18 is added to the number, its digits are reversed. Then find the number. *
Answers
Given:
- Sum of digits of a number = 6
- After adding 18 to it, digits get reversed.
To find:
- The number.
Assumption:
- Let the unit digit and tens digit of the number be x and y respectively.
Solution:
The number = 10y + x (y is the tens digit)...
According to question,
x + y = 6 ------------(i)
And,
10y + x + 18 = 10x + y
=> 9x - 9y = 18
=> x - y = 2 -------------(ii)
Adding (i) & (ii),
=> x + y + x - y = 6 + 2
=> 2x = 8
=> x = 4
So,
=> x + y = 6
=> 4 + y = 6
=> y = 2.
So,
The number = 10y + x => 10*2 + 4 => 24.
The number is 24.
HOPE IT HELPS!!!!
SOLUTION
Let the number in unit place be 'x' .
Let the number in ten's place be 'y' .
So the two digit number is 10y+x
∵ Given that the sum of digits is 6.
x + y = 6 (1)
∵ Given that the if 18 is added to the number, its digits are reversed.
10y + x + 18 = 10x + y
10x + y - 10 y + x =18
9x - 9y = 18
On dividing throughout by 9,
x - y = 2(2)
Now , Let us solve the two equations to find the value of x and y.
x + y = 6
x - y = 2
2x = 8
∵ 2x = 8
Value of x = 4
To find the value of y substitute the value of 'x' in (2)
4 - y = 2
- y = 2 - 4
- y = -2
y = 2
Value of y = 2
Now let us find the two digit number 10y + x , by substituting the values of y and x respectively.