A two digit number is such that the sum of its digit is 8.if 54 is subtracted from the number, its digit are reversed find the number
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A two digit number is such that the sum of its digit is 8.
the number can be 44
therefore,4+4=8
if 54 is subtracted from the number,then 54-44=10
its digit are reversed,then 01
Answered by
1
Hi there!
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
¶¶¶ SOLUTION :
In a two digit No.,
Let Units digit be x
and Tens digit = (8-x)
{°•° Given that Sum of digits is 8
x + (8-x) = 8}
Two digit No. = (10 × face value of tens' place digit) + (1 × face value of one' s place digit)
=> Original No. = 10(8-x) + x
If the digits are reversed, New No. is formed
=> New No. = 10x + (8-x)
Given that,
Original No. - 54 = New No.
=> Original No. - New No. = 54
=> 10(8-x)+x - [10x+(8-x)] = 54
=> 80-10x+x - 10x -8x+x = 54
=> -26x= 54 -80
=> x = 1
•°• Unit's digit = x = 1
& Tens digit = (8-x) = (8-1) = 7
•°• Original No. = 71
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
¶¶¶ VERIFICATION:
No. = 71
• Sum of digits = 8
If digits are reversed,
New No. = 17
Original No.- 54 = New No.
71 - 54 = 17
17 = 17
•°• Given Data Matched
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Hope it helps
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
¶¶¶ SOLUTION :
In a two digit No.,
Let Units digit be x
and Tens digit = (8-x)
{°•° Given that Sum of digits is 8
x + (8-x) = 8}
Two digit No. = (10 × face value of tens' place digit) + (1 × face value of one' s place digit)
=> Original No. = 10(8-x) + x
If the digits are reversed, New No. is formed
=> New No. = 10x + (8-x)
Given that,
Original No. - 54 = New No.
=> Original No. - New No. = 54
=> 10(8-x)+x - [10x+(8-x)] = 54
=> 80-10x+x - 10x -8x+x = 54
=> -26x= 54 -80
=> x = 1
•°• Unit's digit = x = 1
& Tens digit = (8-x) = (8-1) = 7
•°• Original No. = 71
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
¶¶¶ VERIFICATION:
No. = 71
• Sum of digits = 8
If digits are reversed,
New No. = 17
Original No.- 54 = New No.
71 - 54 = 17
17 = 17
•°• Given Data Matched
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Hope it helps
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