Question

 A two-digit number is such that the sum of its digits is 8. If the tens digit is 2 more than the ones digit, find the number.​

Answer 1

Answer:

Let the digits of the number be:

x and y

Ten’s place digit = x

One’s place digit = y

⇒ x = y+2

y + (y+2) = 8

2y + 2 = 8

2y = 8-2

2y = 6

y = 6/2

y = 3

One’s place digit = 3

Ten’s place digit = 3+2

= 5

Number formed = 53

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