Question

A two digit number is such that the sum of its digits is 8. if 54 is subtracted from the number, its digits are reserved. find the number.

Answer 1

$\huge \boxed{ \mathbb{ \ulcorner ANSWER: \urcorner}}$



$\boxed{See \: the \: attachment \: for \: your \: answer.}$



$\boxed{ \mathbb{LINEAR \: EQUATIONS \: IN \: TWO \: VARIABLES.}}$



✔✔ Hence, it is solved ✅✅.

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$\huge \bf{ \# \mathbb{B}e \mathbb{B}rainly.}$

Answer 2

Heya!!

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Let the no be xy.

A/Q ;

x+y = 8 .. Eq1.

Form of the number is 10x + y.

In second case;

=) 10x + y - 54 = 10y +x

=) 10x - x +y - 10y = 54

=) 9(x-y) = 54

=) x -y = 6 .. Eq2.


Add both eq;

=) 2x = 14

=) x = 14/2 = 7

Put the value of x in eq1:

=) 7+y = 8

=) y = 8-7 = 1

Hence number is in Form 10*7 + 1 = 71

Hope it helps uh!!