Question

a two digit number is such that the tens digit exceeds twice the unit digit by 2 and the number obtained by interchanging the digits is 5 more than 3 times the sum of the digits find the two digits of numbers

Answer 1

Let the number be represented by xy  

x in ten's place  

x-2y=2...............(1)  

10y+x= 3(x+y) +5  

10y+x= 3x+3y+5  

7y-2x=5...............(2)  

1 x -2 y = 2 .............1  

-2 x + 7 y = 5 .............2  

Eliminate y  

multiply (1)by 7  

Multiply (2) by 2  

 

7 x -14 y = 14  

-4 x + 14 y = 10  

Add the two equations  

3 x = 24  

/ 3  

x = 8  

plug value of x in (1)  

1 x -2 y = 2  

8 -2y = 2  

-2y =2 -8

-2y = -6  

y=3  

the number is 83

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Answer 2

Answer:

ANSWER

Let us assume number as 10x+y

Let us assume number as 10x+yFrom the question, we have x=2y+2

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5⇒7y−4y−4=5

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5⇒7y−4y−4=5⇒3y=9

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5⇒7y−4y−4=5⇒3y=9⇒y=3

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5⇒7y−4y−4=5⇒3y=9⇒y=3So, x=8

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5⇒7y−4y−4=5⇒3y=9⇒y=3So, x=8Therefore, the two-digit number is

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5⇒7y−4y−4=5⇒3y=9⇒y=3So, x=8Therefore, the two-digit number is =10x+ y

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5⇒7y−4y−4=5⇒3y=9⇒y=3So, x=8Therefore, the two-digit number is =10x+ y=10*8+3

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5⇒7y−4y−4=5⇒3y=9⇒y=3So, x=8Therefore, the two-digit number is =10x+ y=10*8+3=83

Let us assume number as 10x+yFrom the question, we have x=2y+2and 10y+x=3(x+y)+5⇒7y−2x=5⇒7y−4y−4=5⇒3y=9⇒y=3So, x=8Therefore, the two-digit number is =10x+ y=10*8+3=83✓✓✓✓✓✓✓