Question

a two digit number is to be formed from the digits 0 1 2 3 4 repetition of the digits is allowed find the probability that the numbers of first prime number second multiple of 4 third multiple of 11​

Answer 1

Answer:

Random Experiment: A two digit number is to be formed from digits 01234

Step-by-step explanation:

S={10,11,12,13,14,20,21,22,23,24,30,31,32,33,34,40,41,42,43,44,}

n(s)=20

Let A be the event that the number formed is prime number

A={11,13,23,31,41,43,}

n(A)=6

P(A)=n(A)÷n(S)

=6÷20

=3/10

Let B be the event that the number formed is multiple is 4

B={12,20,24,32,40,44}

n(B)=6

p(B)=n(B)÷p(S)

=6÷20

=3/10

Let C be the event that the number formed is multiple of 11

C={11,22,33,44}

n(C)=4

P(C)=n(C)÷n(S)

=4÷20

=5

Answer 2

Step-by-step explanation:

Answer:

Random Experiment: A two digit number is to be formed from digits 01234

Step-by-step explanation:

S={10,11,12,13,14,20,21,22,23,24,30,31,32,33,34,40,41,42,43,44,}

n(s)=20

Let A be the event that the number formed is prime number

A={11,13,23,31,41,43,}

n(A)=6

P(A)=n(A)÷n(S)

=6÷20

=3/10

Let B be the event that the number formed is multiple is 4

B={12,20,24,32,40,44}

n(B)=6

p(B)=n(B)÷p(S)

=6÷20

=3/10

Let C be the event that the number formed is multiple of 11

C={11,22,33,44}

n(C)=4

P(C)=n(C)÷n(S)

=4÷20

=5