Question

A two-digit number of which tens digit exceeds unit digit by 5. The number itself is 8 times the sum of
its digits. Find the number,
​

Answer 1

Step-by-step explanation:

Let us assume x and y are the digits of a two-digit number

Therefore, the two-digit number = 10x + y

Given:

x = y + 5 -----------1

Also given:

10x + y = 8 (x + y)

10x + y = 8x + 8y

2x = 7y --------------2

Substitute the value of x from eqn 1 in eqn 2

2 (y + 5) = 7y

2y + 10 = 7y

5y = 10

y = 2

Therefore, x = y + 5 = 2 + 5 = 7

Therefore, the two-digit number = 10x + y = (10 * 7) + 2 = 72

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Answer 2

Answer: the required number is 72.

Step-by-step explanation:

Let us assume x and y are the digits of a two-digit number

Therefore, the two-digit number = 10x + y

Given:

x = y + 5 -----------1

Also given:

10x + y = 8 (x + y)

10x + y = 8x + 8y

2x = 7y --------------2

Substitute the value of x from eqn 1 in eqn 2

2 (y + 5) = 7y

2y + 10 = 7y

5y = 10

y = 2

Therefore, x = y + 5 = 2 + 5 = 7

Therefore, the two-digit number = 10x + y = (10 * 7) + 2 = 72

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