Question

A two digit number of which tens digit exceeds unit digits by 5. The number itself is 8 times the sum of its digit . Find the number

Answer 1

let the ones digit number be x
therefore other is x+5
atq
10(x+5)+x=8(x+5+x)
10x+50+x=16x+40
taking variable terms right side and numerical terms left side
10=5x
x=2
so the tens digit no. is 2+5=7
the no.is=72

Answer 2

Let us assume x and y are the
digits of a two-digit number

Therefore, the two-digit number =
10x + y

Given:

x = y + 5 -----------1

Also given:

10x + y = 8 (x + y)

10x + y = 8x + 8y

2x = 7y --------------2

Substitute the value of x from eqn
1 in eqn 2

2 (y + 5) = 7y

2y + 10 = 7y

5y = 10

y = 2

Therefore, x = y + 5 = 2 + 5 = 7