A two digit number of which tens digit excessively units digit by 5 the number is itself is 8 times the sum of the digit and the number
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Let us assume x and y are the digits of a two-digit number Therefore, the two-digit number = 10x + y Given: x = y + 5 -----------1 Also given: 10x + y = 8 (x + y) 10x + y = 8x + 8y 2x = 7y --------------2 Substitute the value of x from eqn 1 in eqn 2 2 (y + 5) = 7y 2y + 10 = 7y 5y = 10 y = 2 Therefore, x = y + 5 = 2 + 5 = 7 Therefore, the two-digit number = 10x + y = (10 * 7) + 2 = 72
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