A two-digit number ‘P’ is 160% of another two-digit number ‘Q’, which is 160% of another two-digit number ‘R’. What is the sum of the numbers P, Q and R?
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2
Answer:
129
step by step explanation:
let the two digit number R be 'x'
R:Q:P = x:160% of x :160% of 160% of x
= x : 1.6x : 2.56x = 1 : 1.6 : 2.56
= 100 : 160 : 256
= 25 : 40 : 64
so the possible maximum sum of such two digit numbers P,Q & R will be
= 25 + 40 + 64 = 129
option(1) will be correct from the picture I provided there .
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